LAB REPORT. TITLE : ANALYSING cast- weigh TABLETS INTRODUCTION: The particle wedge out is entrap to be the fourth most wide element in the macrocosms crust. It is encountered in every biological system. Existing in 2 oxidation states Fe (ii) and Fe (iii), it is an important fragment of proteins. In humans, the majority of the protein found is in the hemoglobin is straighten out which totals to about 4-6 grams of iron. Obtained from dietary food for thought such(prenominal) ad vegetables, egg-yolk and causes anemia when deficient. beseech tablets contain iron (ii) sulphate . This main aim of this experimentation is to determine the percentage of iron in a type of an iron salt. MATERIALS/APPARATUS: Beaker- 50cm3 volumetrical Flask-250cm3 Conical Flask- Burette-50cm3 Pipette-25cm3 Diammonium bid (ii) Sulphate 0.1M sulfuric Acid 0.01M Potassium Manganate (vii) Beaker Digital final stage - 3. d.p METHOD: 5g of Diammonium iron (ii) sulphate is weighed and dissolved into 100cm3 of 0.1M Sulphuric Acid. The decide was indeed poured into a 250cm3 volumetric flask including all the washings. The solution, was and so made up to the 250cm3 order with distilled water. RESULTS: Table 1 The table preceding(prenominal) shows the titer value when Iron solution was titrated against potassium Manganate (vii). subnormality: The Equation for the reaction is: 5Fe2+ + MnO4- +8H+ ? 5Fe3+ + Mn2+ + 4H2O 1.

No of counterspyes of MnO2 n = (C*V) V=0.03245 dm3 C= 0.01335Mol dm3 m 0.03245 dm3 * 0.01335 Mol dm3 = 4.33 * 10-4 2. No of Moles of Fe2+ in 25cm3 of the solution. 5Fe2+ + MnO4- +8H+ ? 5Fe3+ + Mn2+ + 4H2O . From the above equation, 5 counterspyes of Fe is formed for every 1 mole of Mno4 ? The number of moles of Fe= No of moles of MnO4- * 5 = 4.33 * 10-4 * 5= 2.166 * 10-4 3. In 25cm3 the no. of moles are= 2.166 * 10-4 In 250cm3 the no of moles of Fe = 2.166 * 10-4 * 5 = 0.02166 4. Mass of Fe = n=m/m.m = ? m= n*m.m = 0.02166Moles * 56 g/mol = 1.213g Mass of FeSO4 n=m/m.m = ?...If you want to get a full essay, order it on our website:
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